131122225542141 has 64 divisors (see below), whose sum is σ = 200449711795200. Its totient is φ = 84666059440128.

The previous prime is 131122225542109. The next prime is 131122225542173. The reversal of 131122225542141 is 141245522221131.

131122225542141 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 2 + 2 + 225 + 5 + 421 + 4 + 1 = 666.

It is an interprime number because it is at equal distance from previous prime (131122225542109) and next prime (131122225542173).

It is not a de Polignac number, because 131122225542141 - 2⁵ = 131122225542109 is a prime.

It is a super-2 number, since 2×131122225542141² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131122225542096 and 131122225542105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131122225542101) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1837619721 + ... + 1837691073.

It is an arithmetic number, because the mean of its divisors is an integer number (3132026746800).

Almost surely, 2^{131122225542141} is an apocalyptic number.

It is an amenable number.

131122225542141 is a deficient number, since it is larger than the sum of its proper divisors (69327486253059).

131122225542141 is a wasteful number, since it uses less digits than its factorization.

131122225542141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86435 (or 86429 counting only the distinct ones).

The product of its digits is 38400, while the sum is 36.

Adding to 131122225542141 its reverse (141245522221131), we get a palindrome (272367747763272).

The spelling of 131122225542141 in words is "one hundred thirty-one trillion, one hundred twenty-two billion, two hundred twenty-five million, five hundred forty-two thousand, one hundred forty-one".