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13112231317 is a prime number
BaseRepresentation
bin11000011011000110…
…01100010110010101
31020211210222100212221
430031203030112111
5203323212400232
610005040342341
7642635061433
oct141543142625
936753870787
1013112231317
115619570509
12265b3149b1
13130c708873
148c5621d53
1551b220897
hex30d8cc595

13112231317 has 2 divisors, whose sum is σ = 13112231318. Its totient is φ = 13112231316.

The previous prime is 13112231309. The next prime is 13112231381. The reversal of 13112231317 is 71313221131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11917215556 + 1195015761 = 109166^2 + 34569^2 .

It is an emirp because it is prime and its reverse (71313221131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13112231317 - 23 = 13112231309 is a prime.

It is a super-2 number, since 2×131122313172 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112231291 and 13112231300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112231387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556115658 + 6556115659.

It is an arithmetic number, because the mean of its divisors is an integer number (6556115659).

Almost surely, 213112231317 is an apocalyptic number.

It is an amenable number.

13112231317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112231317 is an equidigital number, since it uses as much as digits as its factorization.

13112231317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 756, while the sum is 25.

Adding to 13112231317 its reverse (71313221131), we get a palindrome (84425452448).

The spelling of 13112231317 in words is "thirteen billion, one hundred twelve million, two hundred thirty-one thousand, three hundred seventeen".