13112300000114 has 96 divisors (see below), whose sum is σ = 23847750561600. Its totient is φ = 5384735314560.

The previous prime is 13112300000113. The next prime is 13112300000119. The reversal of 13112300000114 is 41100000321131.

It is a super-2 number, since 2×13112300000114² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112300000092 and 13112300000101.

It is not an unprimeable number, because it can be changed into a prime (13112300000113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1549729844 + ... + 1549738304.

It is an arithmetic number, because the mean of its divisors is an integer number (248414068350).

Almost surely, 2^{13112300000114} is an apocalyptic number.

13112300000114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

13112300000114 is a deficient number, since it is larger than the sum of its proper divisors (10735450561486).

13112300000114 is a wasteful number, since it uses less digits than its factorization.

13112300000114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12568 (or 12561 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13112300000114 its reverse (41100000321131), we get a palindrome (54212300321245).

The spelling of 13112300000114 in words is "thirteen trillion, one hundred twelve billion, three hundred million, one hundred fourteen", and thus it is an aban number.