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13112303130000 = 2432541111913103
BaseRepresentation
bin1011111011001111001000…
…1010111001010110010000
31201102112010221122122001200
42332303302022321112100
53204312444100130000
643515413042231200
72522222044430514
oct276636212712620
951375127578050
1013112303130000
1141a5995309528
121579303955500
1374163c385029
143348d3050144
1517b133a6d500
hexbecf22b9590

13112303130000 has 300 divisors, whose sum is σ = 45863242064640. Its totient is φ = 3496032864000.

The previous prime is 13112303129993. The next prime is 13112303130023. The reversal of 13112303130000 is 3130321131.

It is a happy number.

13112303130000 is a `hidden beast` number, since 1 + 311 + 23 + 0 + 31 + 300 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (300).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 1000703449 + ... + 1000716551.

Almost surely, 213112303130000 is an apocalyptic number.

13112303130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112303130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22931621032320).

13112303130000 is an abundant number, since it is smaller than the sum of its proper divisors (32750938934640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112303130000 is a wasteful number, since it uses less digits than its factorization.

13112303130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24256 (or 24232 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 13112303130000 its reverse (3130321131), we get a palindrome (13115433451131).

The spelling of 13112303130000 in words is "thirteen trillion, one hundred twelve billion, three hundred three million, one hundred thirty thousand".