Base | Representation |
---|---|
bin | 10011000101001011011… |
… | …111011001001110001111 |
3 | 11122100111222111010012210 |
4 | 103011023133121032033 |
5 | 132440400233440010 |
6 | 2442212122401503 |
7 | 163506353150241 |
oct | 23051337311617 |
9 | 4570458433183 |
10 | 1311231546255 |
11 | 4660aa02a124 |
12 | 192160960293 |
13 | 96857ca2ab7 |
14 | 4766d0d0091 |
15 | 24194ea0b20 |
hex | 1314b7d938f |
1311231546255 has 64 divisors (see below), whose sum is σ = 2212588800000. Its totient is φ = 661258847232.
The previous prime is 1311231546223. The next prime is 1311231546319. The reversal of 1311231546255 is 5526451321131.
It is not a de Polignac number, because 1311231546255 - 25 = 1311231546223 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 609024259 + ... + 609026411.
It is an arithmetic number, because the mean of its divisors is an integer number (34571700000).
Almost surely, 21311231546255 is an apocalyptic number.
1311231546255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1311231546255 is a deficient number, since it is larger than the sum of its proper divisors (901357253745).
1311231546255 is a wasteful number, since it uses less digits than its factorization.
1311231546255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5248.
The product of its digits is 108000, while the sum is 39.
Adding to 1311231546255 its reverse (5526451321131), we get a palindrome (6837682867386).
The spelling of 1311231546255 in words is "one trillion, three hundred eleven billion, two hundred thirty-one million, five hundred forty-six thousand, two hundred fifty-five".
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