Base | Representation |
---|---|
bin | 1011111011001111001111… |
… | …0110110110110010001101 |
3 | 1201102112012220220110210211 |
4 | 2332303303312312302031 |
5 | 3204313023321243203 |
6 | 43515415533002421 |
7 | 2522222540122051 |
oct | 276636366666215 |
9 | 51375186813724 |
10 | 13112331431053 |
11 | 41a59aa289528 |
12 | 1579311323411 |
13 | 7416451b390a |
14 | 3348d6ad9c61 |
15 | 17b1362adc6d |
hex | becf3db6c8d |
13112331431053 has 32 divisors (see below), whose sum is σ = 13638223872000. Its totient is φ = 12597787440000.
The previous prime is 13112331431021. The next prime is 13112331431083. The reversal of 13112331431053 is 35013413321131.
It is a cyclic number.
It is not a de Polignac number, because 13112331431053 - 25 = 13112331431021 is a prime.
It is a super-3 number, since 3×131123314310533 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13112331431083) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 757973398 + ... + 757990696.
It is an arithmetic number, because the mean of its divisors is an integer number (426194496000).
Almost surely, 213112331431053 is an apocalyptic number.
It is an amenable number.
13112331431053 is a deficient number, since it is larger than the sum of its proper divisors (525892440947).
13112331431053 is a wasteful number, since it uses less digits than its factorization.
13112331431053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18433.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 13112331431053 its reverse (35013413321131), we get a palindrome (48125744752184).
The spelling of 13112331431053 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty-one million, four hundred thirty-one thousand, fifty-three".
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