Base | Representation |
---|---|
bin | 1011111011001111001111… |
… | …0110110110110010001110 |
3 | 1201102112012220220110210212 |
4 | 2332303303312312302032 |
5 | 3204313023321243204 |
6 | 43515415533002422 |
7 | 2522222540122052 |
oct | 276636366666216 |
9 | 51375186813725 |
10 | 13112331431054 |
11 | 41a59aa289529 |
12 | 1579311323412 |
13 | 7416451b390b |
14 | 3348d6ad9c62 |
15 | 17b1362adc6e |
hex | becf3db6c8e |
13112331431054 has 4 divisors (see below), whose sum is σ = 19668497146584. Its totient is φ = 6556165715526.
The previous prime is 13112331431021. The next prime is 13112331431083. The reversal of 13112331431054 is 45013413321131.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×131123314310543 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13112331431054.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278082857762 + ... + 3278082857765.
It is an arithmetic number, because the mean of its divisors is an integer number (4917124286646).
Almost surely, 213112331431054 is an apocalyptic number.
13112331431054 is a deficient number, since it is larger than the sum of its proper divisors (6556165715530).
13112331431054 is an equidigital number, since it uses as much as digits as its factorization.
13112331431054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6556165715529.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 13112331431054 its reverse (45013413321131), we get a palindrome (58125744752185).
The spelling of 13112331431054 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty-one million, four hundred thirty-one thousand, fifty-four".
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