1311243154231 has 2 divisors, whose sum is σ = 1311243154232. Its totient is φ = 1311243154230.

The previous prime is 1311243154213. The next prime is 1311243154259. The reversal of 1311243154231 is 1324513421131.

It is a happy number.

Together with previous prime (1311243154213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (1324513421131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311243154231 - 2¹¹ = 1311243152183 is a prime.

It is a super-3 number, since 3×1311243154231³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1311243154193 and 1311243154202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311243154201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655621577115 + 655621577116.

It is an arithmetic number, because the mean of its divisors is an integer number (655621577116).

Almost surely, 2^{1311243154231} is an apocalyptic number.

1311243154231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311243154231 is an equidigital number, since it uses as much as digits as its factorization.

1311243154231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8640, while the sum is 31.

Adding to 1311243154231 its reverse (1324513421131), we get a palindrome (2635756575362).

The spelling of 1311243154231 in words is "one trillion, three hundred eleven billion, two hundred forty-three million, one hundred fifty-four thousand, two hundred thirty-one".