Base | Representation |
---|---|
bin | 10011000101001100001… |
… | …101000010100110001000 |
3 | 11122100112211000001101221 |
4 | 103011030031002212020 |
5 | 132440411314342300 |
6 | 2442213231051424 |
7 | 163506556645336 |
oct | 23051415024610 |
9 | 4570484001357 |
10 | 1311243512200 |
11 | 466105862336 |
12 | 192164970b74 |
13 | 9685a60243b |
14 | 47670926b56 |
15 | 2419606631a |
hex | 1314c342988 |
1311243512200 has 24 divisors (see below), whose sum is σ = 3048641166330. Its totient is φ = 524497404800.
The previous prime is 1311243512177. The next prime is 1311243512273. The reversal of 1311243512200 is 22153421131.
It can be written as a sum of positive squares in 3 ways, for example, as 1050005991204 + 261237520996 = 1024698^2 + 511114^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3278108581 + ... + 3278108980.
Almost surely, 21311243512200 is an apocalyptic number.
1311243512200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311243512200 is an abundant number, since it is smaller than the sum of its proper divisors (1737397654130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311243512200 is a wasteful number, since it uses less digits than its factorization.
1311243512200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6556217577 (or 6556217568 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1311243512200 its reverse (22153421131), we get a palindrome (1333396933331).
The spelling of 1311243512200 in words is "one trillion, three hundred eleven billion, two hundred forty-three million, five hundred twelve thousand, two hundred".
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