Base | Representation |
---|---|
bin | 1011111011001111111000… |
… | …0011010100100101011111 |
3 | 1201102112122211202012111221 |
4 | 2332303332003110211133 |
5 | 3204313401113033012 |
6 | 43515444522554211 |
7 | 2522230015001602 |
oct | 276637603244537 |
9 | 51375584665457 |
10 | 13112502471007 |
11 | 41a5a87891365 |
12 | 157935a668967 |
13 | 74167176b3a4 |
14 | 334911700339 |
15 | 17b1462e7507 |
hex | becfe0d495f |
13112502471007 has 2 divisors, whose sum is σ = 13112502471008. Its totient is φ = 13112502471006.
The previous prime is 13112502470957. The next prime is 13112502471017. The reversal of 13112502471007 is 70017420521131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112502471007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112502471017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556251235503 + 6556251235504.
It is an arithmetic number, because the mean of its divisors is an integer number (6556251235504).
Almost surely, 213112502471007 is an apocalyptic number.
13112502471007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112502471007 is an equidigital number, since it uses as much as digits as its factorization.
13112502471007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11760, while the sum is 34.
Adding to 13112502471007 its reverse (70017420521131), we get a palindrome (83129922992138).
The spelling of 13112502471007 in words is "thirteen trillion, one hundred twelve billion, five hundred two million, four hundred seventy-one thousand, seven".
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