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13112502471007 is a prime number
BaseRepresentation
bin1011111011001111111000…
…0011010100100101011111
31201102112122211202012111221
42332303332003110211133
53204313401113033012
643515444522554211
72522230015001602
oct276637603244537
951375584665457
1013112502471007
1141a5a87891365
12157935a668967
1374167176b3a4
14334911700339
1517b1462e7507
hexbecfe0d495f

13112502471007 has 2 divisors, whose sum is σ = 13112502471008. Its totient is φ = 13112502471006.

The previous prime is 13112502470957. The next prime is 13112502471017. The reversal of 13112502471007 is 70017420521131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112502471007 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112502471017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556251235503 + 6556251235504.

It is an arithmetic number, because the mean of its divisors is an integer number (6556251235504).

Almost surely, 213112502471007 is an apocalyptic number.

13112502471007 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112502471007 is an equidigital number, since it uses as much as digits as its factorization.

13112502471007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11760, while the sum is 34.

Adding to 13112502471007 its reverse (70017420521131), we get a palindrome (83129922992138).

The spelling of 13112502471007 in words is "thirteen trillion, one hundred twelve billion, five hundred two million, four hundred seventy-one thousand, seven".