13112511400330 has 32 divisors (see below), whose sum is σ = 23657766739200. Its totient is φ = 5232729123072.

The previous prime is 13112511400309. The next prime is 13112511400343. The reversal of 13112511400330 is 3300411521131.

It is a junction number, because it is equal to n+sod(n) for n = 13112511400295 and 13112511400304.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 77280226 + ... + 77449714.

It is an arithmetic number, because the mean of its divisors is an integer number (739305210600).

Almost surely, 2^{13112511400330} is an apocalyptic number.

13112511400330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13112511400330 is a deficient number, since it is larger than the sum of its proper divisors (10545255338870).

13112511400330 is a wasteful number, since it uses less digits than its factorization.

13112511400330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187558.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 13112511400330 its reverse (3300411521131), we get a palindrome (16412922921461).

The spelling of 13112511400330 in words is "thirteen trillion, one hundred twelve billion, five hundred eleven million, four hundred thousand, three hundred thirty".