13112514102130 has 32 divisors (see below), whose sum is σ = 23794005026880. Its totient is φ = 5202615485760.

The previous prime is 13112514102071. The next prime is 13112514102139. The reversal of 13112514102130 is 3120141521131.

It is a junction number, because it is equal to n+sod(n) for n = 13112514102095 and 13112514102104.

It is not an unprimeable number, because it can be changed into a prime (13112514102139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9402460 + ... + 10706599.

It is an arithmetic number, because the mean of its divisors is an integer number (743562657090).

Almost surely, 2^{13112514102130} is an apocalyptic number.

13112514102130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13112514102130 is a deficient number, since it is larger than the sum of its proper divisors (10681490924750).

13112514102130 is a wasteful number, since it uses less digits than its factorization.

13112514102130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20109594.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 13112514102130 its reverse (3120141521131), we get a palindrome (16232655623261).

The spelling of 13112514102130 in words is "thirteen trillion, one hundred twelve billion, five hundred fourteen million, one hundred two thousand, one hundred thirty".