Base | Representation |
---|---|
bin | 10011000101001111100… |
… | …101011010110110100101 |
3 | 11122100200202201211222211 |
4 | 103011033211122312211 |
5 | 132441020330002121 |
6 | 2442223014523421 |
7 | 163511146042054 |
oct | 23051745326645 |
9 | 4570622654884 |
10 | 1311300234661 |
11 | 4661348847aa |
12 | 19217b966571 |
13 | 968692a2621 |
14 | 4767829039b |
15 | 2419b01cce1 |
hex | 1314f95ada5 |
1311300234661 has 2 divisors, whose sum is σ = 1311300234662. Its totient is φ = 1311300234660.
The previous prime is 1311300234653. The next prime is 1311300234667. The reversal of 1311300234661 is 1664320031131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1116118296225 + 195181938436 = 1056465^2 + 441794^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311300234661 - 23 = 1311300234653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311300234667) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655650117330 + 655650117331.
It is an arithmetic number, because the mean of its divisors is an integer number (655650117331).
Almost surely, 21311300234661 is an apocalyptic number.
It is an amenable number.
1311300234661 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311300234661 is an equidigital number, since it uses as much as digits as its factorization.
1311300234661 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 1311300234661 its reverse (1664320031131), we get a palindrome (2975620265792).
The spelling of 1311300234661 in words is "one trillion, three hundred eleven billion, three hundred million, two hundred thirty-four thousand, six hundred sixty-one".
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