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1311303112117 is a prime number
BaseRepresentation
bin10011000101001111110…
…000011001010110110101
311122100200222011001010021
4103011033300121112311
5132441022044041432
62442223200325141
7163511212355125
oct23051760312665
94570628131107
101311303112117
1146613646a669
121921809137b1
1396869a6c26b
14476787dcc85
152419b3da697
hex1314fc195b5

1311303112117 has 2 divisors, whose sum is σ = 1311303112118. Its totient is φ = 1311303112116.

The previous prime is 1311303112019. The next prime is 1311303112127. The reversal of 1311303112117 is 7112113031131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1008897704721 + 302405407396 = 1004439^2 + 549914^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311303112117 - 227 = 1311168894389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311303112091 and 1311303112100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311303112127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655651556058 + 655651556059.

It is an arithmetic number, because the mean of its divisors is an integer number (655651556059).

Almost surely, 21311303112117 is an apocalyptic number.

It is an amenable number.

1311303112117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311303112117 is an equidigital number, since it uses as much as digits as its factorization.

1311303112117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378, while the sum is 25.

Adding to 1311303112117 its reverse (7112113031131), we get a palindrome (8423416143248).

The spelling of 1311303112117 in words is "one trillion, three hundred eleven billion, three hundred three million, one hundred twelve thousand, one hundred seventeen".