Base | Representation |
---|---|
bin | 1011111011010001111101… |
… | …0110011101100000111000 |
3 | 1201102121002202222100102021 |
4 | 2332310133112131200320 |
5 | 3204321022122331230 |
6 | 43520020201044224 |
7 | 2522246610404026 |
oct | 276643726354070 |
9 | 51377082870367 |
10 | 13113061136440 |
11 | 41a6244177a31 |
12 | 1579495786674 |
13 | 741730423b55 |
14 | 3349659a7716 |
15 | 17b17a39cc7a |
hex | bed1f59d838 |
13113061136440 has 16 divisors (see below), whose sum is σ = 29504387557080. Its totient is φ = 5245224454560.
The previous prime is 13113061136431. The next prime is 13113061136443. The reversal of 13113061136440 is 4463116031131.
It is a junction number, because it is equal to n+sod(n) for n = 13113061136396 and 13113061136405.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113061136443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163913264166 + ... + 163913264245.
Almost surely, 213113061136440 is an apocalyptic number.
13113061136440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13113061136440 is an abundant number, since it is smaller than the sum of its proper divisors (16391326420640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13113061136440 is a wasteful number, since it uses less digits than its factorization.
13113061136440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 327826528422 (or 327826528418 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 34.
Adding to 13113061136440 its reverse (4463116031131), we get a palindrome (17576177167571).
The spelling of 13113061136440 in words is "thirteen trillion, one hundred thirteen billion, sixty-one million, one hundred thirty-six thousand, four hundred forty".
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