Base | Representation |
---|---|
bin | 111101000100000000… |
… | …1000100010110100110 |
3 | 110112110202010000021020 |
4 | 1322020001010112212 |
5 | 4122024014001410 |
6 | 140124000232010 |
7 | 12321356053056 |
oct | 1721001042646 |
9 | 415422100236 |
10 | 131131000230 |
11 | 5068103836a |
12 | 214b760b606 |
13 | c49a2ba839 |
14 | 64bd797566 |
15 | 36272bea70 |
hex | 1e880445a6 |
131131000230 has 16 divisors (see below), whose sum is σ = 314714400624. Its totient is φ = 34968266720.
The previous prime is 131131000201. The next prime is 131131000237. The reversal of 131131000230 is 32000131131.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131131000237) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2185516641 + ... + 2185516700.
It is an arithmetic number, because the mean of its divisors is an integer number (19669650039).
Almost surely, 2131131000230 is an apocalyptic number.
131131000230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131131000230 is an abundant number, since it is smaller than the sum of its proper divisors (183583400394).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131131000230 is a wasteful number, since it uses less digits than its factorization.
131131000230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4371033351.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 131131000230 its reverse (32000131131), we get a palindrome (163131131361).
The spelling of 131131000230 in words is "one hundred thirty-one billion, one hundred thirty-one million, two hundred thirty", and thus it is an aban number.
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