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1311310163 is a prime number
BaseRepresentation
bin100111000101001…
…0000000101010011
310101101110110101002
41032022100011103
510141143411123
6334041532215
744331644462
oct11612200523
93341413332
101311310163
11613222809
123071a406b
1317b897c97
14c62269d9
157a1c6528
hex4e290153

1311310163 has 2 divisors, whose sum is σ = 1311310164. Its totient is φ = 1311310162.

The previous prime is 1311310157. The next prime is 1311310183. The reversal of 1311310163 is 3610131131.

It is a happy number.

It is an a-pointer prime, because the next prime (1311310183) can be obtained adding 1311310163 to its sum of digits (20).

It is a weak prime.

It is an emirp because it is prime and its reverse (3610131131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311310163 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311310183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655655081 + 655655082.

It is an arithmetic number, because the mean of its divisors is an integer number (655655082).

Almost surely, 21311310163 is an apocalyptic number.

1311310163 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311310163 is an equidigital number, since it uses as much as digits as its factorization.

1311310163 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

The square root of 1311310163 is about 36212.0168314332. The cubic root of 1311310163 is about 1094.5488332674.

Adding to 1311310163 its reverse (3610131131), we get a palindrome (4921441294).

The spelling of 1311310163 in words is "one billion, three hundred eleven million, three hundred ten thousand, one hundred sixty-three".