13113111110010 has 32 divisors (see below), whose sum is σ = 31471701049152. Its totient is φ = 3496803586560.

The previous prime is 13113111109997. The next prime is 13113111110041. The reversal of 13113111110010 is 1001111131131.

13113111110010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2652117 + ... + 5767143.

It is an arithmetic number, because the mean of its divisors is an integer number (983490657786).

Almost surely, 2^{13113111110010} is an apocalyptic number.

13113111110010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13113111110010 is an abundant number, since it is smaller than the sum of its proper divisors (18358589939142).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113111110010 is a wasteful number, since it uses less digits than its factorization.

13113111110010 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3255358.

The product of its (nonzero) digits is 9, while the sum is 15.

Adding to 13113111110010 its reverse (1001111131131), we get a palindrome (14114222241141).

The spelling of 13113111110010 in words is "thirteen trillion, one hundred thirteen billion, one hundred eleven million, one hundred ten thousand, ten".