Base | Representation |
---|---|
bin | 1011111011010010001001… |
… | …1100110001100110000011 |
3 | 1201102121020101210112211221 |
4 | 2332310202130301212003 |
5 | 3204321123424420303 |
6 | 43520025255215511 |
7 | 2522251111314652 |
oct | 276644234614603 |
9 | 51377211715757 |
10 | 13113113123203 |
11 | 41a62705553a5 |
12 | 15794ab077597 |
13 | 74173b126652 |
14 | 33496c85b199 |
15 | 17b17ec1b4bd |
hex | bed22731983 |
13113113123203 has 2 divisors, whose sum is σ = 13113113123204. Its totient is φ = 13113113123202.
The previous prime is 13113113123183. The next prime is 13113113123207. The reversal of 13113113123203 is 30232131131131.
13113113123203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113113123203 - 221 = 13113111026051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13113113123207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556556561601 + 6556556561602.
It is an arithmetic number, because the mean of its divisors is an integer number (6556556561602).
Almost surely, 213113113123203 is an apocalyptic number.
13113113123203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113113123203 is an equidigital number, since it uses as much as digits as its factorization.
13113113123203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 13113113123203 its reverse (30232131131131), we get a palindrome (43345244254334).
The spelling of 13113113123203 in words is "thirteen trillion, one hundred thirteen billion, one hundred thirteen million, one hundred twenty-three thousand, two hundred three".
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