Base | Representation |
---|---|
bin | 1011111011010010001110… |
… | …1001110100100000011111 |
3 | 1201102121021210210122221201 |
4 | 2332310203221310200133 |
5 | 3204321144112221343 |
6 | 43520031300140331 |
7 | 2522251445064256 |
oct | 276644351644037 |
9 | 51377253718851 |
10 | 13113133320223 |
11 | 41a628099a752 |
12 | 15794b59976a7 |
13 | 741742378651 |
14 | 3349713d779d |
15 | 17b1818aa94d |
hex | bed23a7481f |
13113133320223 has 2 divisors, whose sum is σ = 13113133320224. Its totient is φ = 13113133320222.
The previous prime is 13113133320193. The next prime is 13113133320233. The reversal of 13113133320223 is 32202333131131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (32202333131131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13113133320223 - 213 = 13113133312031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13113133320191 and 13113133320200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113133320233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556566660111 + 6556566660112.
It is an arithmetic number, because the mean of its divisors is an integer number (6556566660112).
Almost surely, 213113133320223 is an apocalyptic number.
13113133320223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113133320223 is an equidigital number, since it uses as much as digits as its factorization.
13113133320223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 13113133320223 its reverse (32202333131131), we get a palindrome (45315466451354).
The spelling of 13113133320223 in words is "thirteen trillion, one hundred thirteen billion, one hundred thirty-three million, three hundred twenty thousand, two hundred twenty-three".
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