131131403044100 has 144 divisors (see below), whose sum is σ = 288958174243200. Its totient is φ = 51647108613120.

The previous prime is 131131403044099. The next prime is 131131403044183. The reversal of 131131403044100 is 1440304131131.

It is a self number, because there is not a number n which added to its sum of digits gives 131131403044100.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10636006736 + ... + 10636019064.

It is an arithmetic number, because the mean of its divisors is an integer number (2006653987800).

Almost surely, 2^{131131403044100} is an apocalyptic number.

131131403044100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131131403044100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (144479087121600).

131131403044100 is an abundant number, since it is smaller than the sum of its proper divisors (157826771199100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131131403044100 is a wasteful number, since it uses less digits than its factorization.

131131403044100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18462 (or 18455 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 131131403044100 its reverse (1440304131131), we get a palindrome (132571707175231).

The spelling of 131131403044100 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, four hundred three million, forty-four thousand, one hundred".