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1311320202013 is a prime number
BaseRepresentation
bin10011000101010000110…
…001100101101100011101
311122100202011022022001101
4103011100301211230131
5132441040432431023
62442225010513101
7163511510543653
oct23052061455435
94570664268041
101311320202013
11466145082548
12192186595791
1396870473c23
144767abaadd3
152419cb641ad
hex13150c65b1d

1311320202013 has 2 divisors, whose sum is σ = 1311320202014. Its totient is φ = 1311320202012.

The previous prime is 1311320202011. The next prime is 1311320202043. The reversal of 1311320202013 is 3102020231131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1293865300324 + 17454901689 = 1137482^2 + 132117^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311320202013 - 21 = 1311320202011 is a prime.

Together with 1311320202011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311320202011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655660101006 + 655660101007.

It is an arithmetic number, because the mean of its divisors is an integer number (655660101007).

Almost surely, 21311320202013 is an apocalyptic number.

It is an amenable number.

1311320202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311320202013 is an equidigital number, since it uses as much as digits as its factorization.

1311320202013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1311320202013 its reverse (3102020231131), we get a palindrome (4413340433144).

The spelling of 1311320202013 in words is "one trillion, three hundred eleven billion, three hundred twenty million, two hundred two thousand, thirteen".