Base | Representation |
---|---|
bin | 1011111011010010011111… |
… | …0000010011100011011101 |
3 | 1201102121110121021112000021 |
4 | 2332310213300103203131 |
5 | 3204321314221112432 |
6 | 43520042155032141 |
7 | 2522253242000266 |
oct | 276644760234335 |
9 | 51377417245007 |
10 | 13113202129117 |
11 | 41a6306817902 |
12 | 1579514a3b651 |
13 | 7417536bac7c |
14 | 33497a5c996d |
15 | 17b18794d697 |
hex | bed27c138dd |
13113202129117 has 2 divisors, whose sum is σ = 13113202129118. Its totient is φ = 13113202129116.
The previous prime is 13113202129099. The next prime is 13113202129129. The reversal of 13113202129117 is 71192120231131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11174385381721 + 1938816747396 = 3342811^2 + 1392414^2 .
It is a cyclic number.
It is not a de Polignac number, because 13113202129117 - 243 = 4317109106909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113202129177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556601064558 + 6556601064559.
It is an arithmetic number, because the mean of its divisors is an integer number (6556601064559).
Almost surely, 213113202129117 is an apocalyptic number.
It is an amenable number.
13113202129117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113202129117 is an equidigital number, since it uses as much as digits as its factorization.
13113202129117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536, while the sum is 34.
The spelling of 13113202129117 in words is "thirteen trillion, one hundred thirteen billion, two hundred two million, one hundred twenty-nine thousand, one hundred seventeen".
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