Base | Representation |
---|---|
bin | 1011111011010010011111… |
… | …0000010100100011000101 |
3 | 1201102121110121021201121002 |
4 | 2332310213300110203011 |
5 | 3204321314221230224 |
6 | 43520042155103045 |
7 | 2522253242015204 |
oct | 276644760244305 |
9 | 51377417251532 |
10 | 13113202133189 |
11 | 41a630681a974 |
12 | 1579514a41a85 |
13 | 7417536bca92 |
14 | 33497a5cb23b |
15 | 17b18794e9ae |
hex | bed27c148c5 |
13113202133189 has 2 divisors, whose sum is σ = 13113202133190. Its totient is φ = 13113202133188.
The previous prime is 13113202133123. The next prime is 13113202133219. The reversal of 13113202133189 is 98133120231131.
13113202133189 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13101395572225 + 11806560964 = 3619585^2 + 108658^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13113202133189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113202133089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556601066594 + 6556601066595.
It is an arithmetic number, because the mean of its divisors is an integer number (6556601066595).
Almost surely, 213113202133189 is an apocalyptic number.
It is an amenable number.
13113202133189 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113202133189 is an equidigital number, since it uses as much as digits as its factorization.
13113202133189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 38.
The spelling of 13113202133189 in words is "thirteen trillion, one hundred thirteen billion, two hundred two million, one hundred thirty-three thousand, one hundred eighty-nine".
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