Base | Representation |
---|---|
bin | 11101110100001110010010… |
… | …001111010011100101111000 |
3 | 122012022002212111220000110220 |
4 | 131310032102033103211320 |
5 | 114141432020100000440 |
6 | 1142521131033540040 |
7 | 36422660453012262 |
oct | 3564162217234570 |
9 | 565262774800426 |
10 | 131132100000120 |
11 | 388678a193043a |
12 | 1285a342b74620 |
13 | 582291c81346b |
14 | 2454b8295ab32 |
15 | 10260a81da8d0 |
hex | 7743923d3978 |
131132100000120 has 256 divisors, whose sum is σ = 403117134497280. Its totient is φ = 34112374732800.
The previous prime is 131132100000113. The next prime is 131132100000131. The reversal of 131132100000120 is 21000001231131.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 131132100000120.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1370093307 + ... + 1370189013.
It is an arithmetic number, because the mean of its divisors is an integer number (1574676306630).
Almost surely, 2131132100000120 is an apocalyptic number.
131132100000120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131132100000120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (201558567248640).
131132100000120 is an abundant number, since it is smaller than the sum of its proper divisors (271985034497160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131132100000120 is a wasteful number, since it uses less digits than its factorization.
131132100000120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97006 (or 97002 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 131132100000120 its reverse (21000001231131), we get a palindrome (152132101231251).
The spelling of 131132100000120 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, one hundred million, one hundred twenty", and thus it is an aban number.
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