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13113211023043 is a prime number
BaseRepresentation
bin1011111011010010100001…
…0010001110111011000011
31201102121111020000101011221
42332310220102032323003
53204321324010214133
643520043113415511
72522253410412145
oct276645022167303
951377436011157
1013113211023043
1141a6310841a5a
121579517a0a597
137417554b3251
1433497b862c95
1517b188608a2d
hexbed2848eec3

13113211023043 has 2 divisors, whose sum is σ = 13113211023044. Its totient is φ = 13113211023042.

The previous prime is 13113211022941. The next prime is 13113211023053. The reversal of 13113211023043 is 34032011231131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13113211023043 - 213 = 13113211014851 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13113211022999 and 13113211023017.

It is not a weakly prime, because it can be changed into another prime (13113211023053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556605511521 + 6556605511522.

It is an arithmetic number, because the mean of its divisors is an integer number (6556605511522).

Almost surely, 213113211023043 is an apocalyptic number.

13113211023043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113211023043 is an equidigital number, since it uses as much as digits as its factorization.

13113211023043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13113211023043 its reverse (34032011231131), we get a palindrome (47145222254174).

The spelling of 13113211023043 in words is "thirteen trillion, one hundred thirteen billion, two hundred eleven million, twenty-three thousand, forty-three".