Base | Representation |
---|---|
bin | 1011111011010010100001… |
… | …0010001110111011000011 |
3 | 1201102121111020000101011221 |
4 | 2332310220102032323003 |
5 | 3204321324010214133 |
6 | 43520043113415511 |
7 | 2522253410412145 |
oct | 276645022167303 |
9 | 51377436011157 |
10 | 13113211023043 |
11 | 41a6310841a5a |
12 | 1579517a0a597 |
13 | 7417554b3251 |
14 | 33497b862c95 |
15 | 17b188608a2d |
hex | bed2848eec3 |
13113211023043 has 2 divisors, whose sum is σ = 13113211023044. Its totient is φ = 13113211023042.
The previous prime is 13113211022941. The next prime is 13113211023053. The reversal of 13113211023043 is 34032011231131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113211023043 - 213 = 13113211014851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13113211022999 and 13113211023017.
It is not a weakly prime, because it can be changed into another prime (13113211023053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556605511521 + 6556605511522.
It is an arithmetic number, because the mean of its divisors is an integer number (6556605511522).
Almost surely, 213113211023043 is an apocalyptic number.
13113211023043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113211023043 is an equidigital number, since it uses as much as digits as its factorization.
13113211023043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13113211023043 its reverse (34032011231131), we get a palindrome (47145222254174).
The spelling of 13113211023043 in words is "thirteen trillion, one hundred thirteen billion, two hundred eleven million, twenty-three thousand, forty-three".
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