Base | Representation |
---|---|
bin | 11101110100001110011111… |
… | …011110101010100100100010 |
3 | 122012022010102222212101200021 |
4 | 131310032133132222210202 |
5 | 114141432443431131320 |
6 | 1142521205050544054 |
7 | 36422666121050002 |
oct | 3564163736524442 |
9 | 565263388771607 |
10 | 131132322130210 |
11 | 388679a6259025 |
12 | 1285a3a543802a |
13 | 582295684859b |
14 | 2454ba4260002 |
15 | 10260bc966daa |
hex | 77439f7aa922 |
131132322130210 has 64 divisors (see below), whose sum is σ = 248218645169664. Its totient is φ = 49827964838400.
The previous prime is 131132322130157. The next prime is 131132322130217. The reversal of 131132322130210 is 12031223231131.
It is a super-2 number, since 2×1311323221302102 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131132322130217) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21525811 + ... + 26937430.
It is an arithmetic number, because the mean of its divisors is an integer number (3878416330776).
Almost surely, 2131132322130210 is an apocalyptic number.
131132322130210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131132322130210 is a deficient number, since it is larger than the sum of its proper divisors (117086323039454).
131132322130210 is a wasteful number, since it uses less digits than its factorization.
131132322130210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48463459.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 131132322130210 its reverse (12031223231131), we get a palindrome (143163545361341).
The spelling of 131132322130210 in words is "one hundred thirty-one trillion, one hundred thirty-two billion, three hundred twenty-two million, one hundred thirty thousand, two hundred ten".
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