Base | Representation |
---|---|
bin | 10011000101010001001… |
… | …001110100010011010101 |
3 | 11122100202121020222101021 |
4 | 103011101021310103111 |
5 | 132441044044201201 |
6 | 2442225355001141 |
7 | 163511615535562 |
oct | 23052111642325 |
9 | 4570677228337 |
10 | 1311326553301 |
11 | 466148720346 |
12 | 1921887391b1 |
13 | 96871888a9b |
14 | 4767b981869 |
15 | 2419d4baea1 |
hex | 131512744d5 |
1311326553301 has 4 divisors (see below), whose sum is σ = 1312923785004. Its totient is φ = 1309729321600.
The previous prime is 1311326553259. The next prime is 1311326553331. The reversal of 1311326553301 is 1033556231131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 485683548100 + 825643005201 = 696910^2 + 908649^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311326553301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311326553331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 798614620 + ... + 798616261.
It is an arithmetic number, because the mean of its divisors is an integer number (328230946251).
Almost surely, 21311326553301 is an apocalyptic number.
It is an amenable number.
1311326553301 is a deficient number, since it is larger than the sum of its proper divisors (1597231703).
1311326553301 is an equidigital number, since it uses as much as digits as its factorization.
1311326553301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1597231702.
The product of its (nonzero) digits is 24300, while the sum is 34.
The spelling of 1311326553301 in words is "one trillion, three hundred eleven billion, three hundred twenty-six million, five hundred fifty-three thousand, three hundred one".
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