Base | Representation |
---|---|
bin | 111101000100000110… |
… | …0100011101100100111 |
3 | 110112110221210000220122 |
4 | 1322020030203230213 |
5 | 4122030301342244 |
6 | 140124144552155 |
7 | 12321423466241 |
oct | 1721014435447 |
9 | 415427700818 |
10 | 131134012199 |
11 | 506828052a3 |
12 | 214b862265b |
13 | c49ab03778 |
14 | 64bdd3d091 |
15 | 36276b71ee |
hex | 1e88323b27 |
131134012199 has 2 divisors, whose sum is σ = 131134012200. Its totient is φ = 131134012198.
The previous prime is 131134012187. The next prime is 131134012211. The reversal of 131134012199 is 991210431131.
It is a balanced prime because it is at equal distance from previous prime (131134012187) and next prime (131134012211).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131134012199 is a prime.
It is a super-2 number, since 2×1311340121992 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131134012169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65567006099 + 65567006100.
It is an arithmetic number, because the mean of its divisors is an integer number (65567006100).
Almost surely, 2131134012199 is an apocalyptic number.
131134012199 is a deficient number, since it is larger than the sum of its proper divisors (1).
131134012199 is an equidigital number, since it uses as much as digits as its factorization.
131134012199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 131134012199 in words is "one hundred thirty-one billion, one hundred thirty-four million, twelve thousand, one hundred ninety-nine".
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