Base | Representation |
---|---|
bin | 11101110100010000001010… |
… | …111100101001010001001110 |
3 | 122012022022002122120100122112 |
4 | 131310100022330221101032 |
5 | 114142000142014320220 |
6 | 1142522104015544022 |
7 | 36423061603346201 |
oct | 3564201274512116 |
9 | 565268078510575 |
10 | 131134125151310 |
11 | 38868740a96506 |
12 | 1285a80922b012 |
13 | 5822b83255788 |
14 | 2454cd58c1938 |
15 | 1026175dba5c5 |
hex | 77440af2944e |
131134125151310 has 32 divisors (see below), whose sum is σ = 242421818237280. Its totient is φ = 51035795425152.
The previous prime is 131134125151303. The next prime is 131134125151331. The reversal of 131134125151310 is 13151521431131.
It is a super-2 number, since 2×1311341251513102 (a number of 29 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 141224672 + ... + 142150188.
It is an arithmetic number, because the mean of its divisors is an integer number (7575681819915).
Almost surely, 2131134125151310 is an apocalyptic number.
131134125151310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131134125151310 is a deficient number, since it is larger than the sum of its proper divisors (111287693085970).
131134125151310 is a wasteful number, since it uses less digits than its factorization.
131134125151310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1308500.
The product of its (nonzero) digits is 5400, while the sum is 32.
Adding to 131134125151310 its reverse (13151521431131), we get a palindrome (144285646582441).
The spelling of 131134125151310 in words is "one hundred thirty-one trillion, one hundred thirty-four billion, one hundred twenty-five million, one hundred fifty-one thousand, three hundred ten".
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