Base | Representation |
---|---|
bin | 111101000100000111… |
… | …0111001001001001010 |
3 | 110112110222221010121011 |
4 | 1322020032321021022 |
5 | 4122030430434310 |
6 | 140124210034134 |
7 | 12321431626003 |
oct | 1721016711112 |
9 | 415428833534 |
10 | 131134624330 |
11 | 50683093196 |
12 | 214b887894a |
13 | c49ac89288 |
14 | 64c005c1aa |
15 | 362778878a |
hex | 1e883b924a |
131134624330 has 32 divisors (see below), whose sum is σ = 241099047936. Its totient is φ = 51330453504.
The previous prime is 131134624267. The next prime is 131134624337. The reversal of 131134624330 is 33426431131.
It is a junction number, because it is equal to n+sod(n) for n = 131134624292 and 131134624301.
It is not an unprimeable number, because it can be changed into a prime (131134624337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4217802 + ... + 4248778.
It is an arithmetic number, because the mean of its divisors is an integer number (7534345248).
Almost surely, 2131134624330 is an apocalyptic number.
131134624330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131134624330 is a deficient number, since it is larger than the sum of its proper divisors (109964423606).
131134624330 is a wasteful number, since it uses less digits than its factorization.
131134624330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40038.
The product of its (nonzero) digits is 15552, while the sum is 31.
The spelling of 131134624330 in words is "one hundred thirty-one billion, one hundred thirty-four million, six hundred twenty-four thousand, three hundred thirty".
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