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13113491483 is a prime number
BaseRepresentation
bin11000011011010000…
…00000000000011011
31020211220100101111202
430031220000000123
5203324023211413
610005123344415
7642651560411
oct141550000033
936756311452
1013113491483
11561a251274
12265b82210b
13130ca5a321
148c586d2b1
1551b3bde58
hex30da0001b

13113491483 has 2 divisors, whose sum is σ = 13113491484. Its totient is φ = 13113491482.

The previous prime is 13113491387. The next prime is 13113491513. The reversal of 13113491483 is 38419431131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13113491483 is a prime.

It is not a weakly prime, because it can be changed into another prime (13113491683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556745741 + 6556745742.

It is an arithmetic number, because the mean of its divisors is an integer number (6556745742).

Almost surely, 213113491483 is an apocalyptic number.

13113491483 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113491483 is an equidigital number, since it uses as much as digits as its factorization.

13113491483 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 38.

The spelling of 13113491483 in words is "thirteen billion, one hundred thirteen million, four hundred ninety-one thousand, four hundred eighty-three".