Base | Representation |
---|---|
bin | 10011000101010101101… |
… | …101111010010101100111 |
3 | 11122100221221100011201201 |
4 | 103011111231322111213 |
5 | 132441223144432241 |
6 | 2442241132103331 |
7 | 163513535430145 |
oct | 23052555722547 |
9 | 4570857304651 |
10 | 1311403124071 |
11 | 46618796a077 |
12 | 1921aa304b47 |
13 | 968846b8331 |
14 | 47687bd4595 |
15 | 241a5093931 |
hex | 13155b7a567 |
1311403124071 has 2 divisors, whose sum is σ = 1311403124072. Its totient is φ = 1311403124070.
The previous prime is 1311403124069. The next prime is 1311403124081. The reversal of 1311403124071 is 1704213041131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1704213041131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311403124071 - 21 = 1311403124069 is a prime.
It is a super-2 number, since 2×13114031240712 (a number of 25 digits) contains 22 as substring.
Together with 1311403124069, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311403124081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655701562035 + 655701562036.
It is an arithmetic number, because the mean of its divisors is an integer number (655701562036).
Almost surely, 21311403124071 is an apocalyptic number.
1311403124071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311403124071 is an equidigital number, since it uses as much as digits as its factorization.
1311403124071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
The spelling of 1311403124071 in words is "one trillion, three hundred eleven billion, four hundred three million, one hundred twenty-four thousand, seventy-one".
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