131140403004311 has 2 divisors, whose sum is σ = 131140403004312. Its totient is φ = 131140403004310.

The previous prime is 131140403004277. The next prime is 131140403004313. The reversal of 131140403004311 is 113400304041131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131140403004311 - 2²⁶ = 131140335895447 is a prime.

Together with 131140403004313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131140403004313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570201502155 + 65570201502156.

It is an arithmetic number, because the mean of its divisors is an integer number (65570201502156).

Almost surely, 2^{131140403004311} is an apocalyptic number.

131140403004311 is a deficient number, since it is larger than the sum of its proper divisors (1).

131140403004311 is an equidigital number, since it uses as much as digits as its factorization.

131140403004311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 131140403004311 its reverse (113400304041131), we get a palindrome (244540707045442).

The spelling of 131140403004311 in words is "one hundred thirty-one trillion, one hundred forty billion, four hundred three million, four thousand, three hundred eleven".