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1311411063317 is a prime number
BaseRepresentation
bin10011000101010110001…
…100001100101000010101
311122100222111021112022212
4103011112030030220111
5132441232213011232
62442242014203205
7163513663054505
oct23052614145025
94570874245285
101311411063317
114661913a1a33
121921b0ab3505
1396886237c04
1447688c9da05
15241a5b10eb2
hex1315630ca15

1311411063317 has 2 divisors, whose sum is σ = 1311411063318. Its totient is φ = 1311411063316.

The previous prime is 1311411063307. The next prime is 1311411063323. The reversal of 1311411063317 is 7133601141131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1219149430801 + 92261632516 = 1104151^2 + 303746^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311411063317 - 240 = 211899435541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311411063307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655705531658 + 655705531659.

It is an arithmetic number, because the mean of its divisors is an integer number (655705531659).

Almost surely, 21311411063317 is an apocalyptic number.

It is an amenable number.

1311411063317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311411063317 is an equidigital number, since it uses as much as digits as its factorization.

1311411063317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4536, while the sum is 32.

The spelling of 1311411063317 in words is "one trillion, three hundred eleven billion, four hundred eleven million, sixty-three thousand, three hundred seventeen".