Base | Representation |
---|---|
bin | 10011000101010110001… |
… | …100001100101000010101 |
3 | 11122100222111021112022212 |
4 | 103011112030030220111 |
5 | 132441232213011232 |
6 | 2442242014203205 |
7 | 163513663054505 |
oct | 23052614145025 |
9 | 4570874245285 |
10 | 1311411063317 |
11 | 4661913a1a33 |
12 | 1921b0ab3505 |
13 | 96886237c04 |
14 | 47688c9da05 |
15 | 241a5b10eb2 |
hex | 1315630ca15 |
1311411063317 has 2 divisors, whose sum is σ = 1311411063318. Its totient is φ = 1311411063316.
The previous prime is 1311411063307. The next prime is 1311411063323. The reversal of 1311411063317 is 7133601141131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1219149430801 + 92261632516 = 1104151^2 + 303746^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311411063317 - 240 = 211899435541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311411063307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655705531658 + 655705531659.
It is an arithmetic number, because the mean of its divisors is an integer number (655705531659).
Almost surely, 21311411063317 is an apocalyptic number.
It is an amenable number.
1311411063317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311411063317 is an equidigital number, since it uses as much as digits as its factorization.
1311411063317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536, while the sum is 32.
The spelling of 1311411063317 in words is "one trillion, three hundred eleven billion, four hundred eleven million, sixty-three thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •