Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …011001011001101000111011 |
3 | 122012022222010120120121202121 |
4 | 131310112223121121220323 |
5 | 114142103444133330243 |
6 | 1142525221204342111 |
7 | 36423430002600361 |
oct | 3564265331315073 |
9 | 565288116517677 |
10 | 131141112011323 |
11 | 388706a6985887 |
12 | 128600390a4937 |
13 | 582372790a87b |
14 | 24553997bb631 |
15 | 102643448b1ed |
hex | 7745ab659a3b |
131141112011323 has 2 divisors, whose sum is σ = 131141112011324. Its totient is φ = 131141112011322.
The previous prime is 131141112011321. The next prime is 131141112011359. The reversal of 131141112011323 is 323110211141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141112011323 - 21 = 131141112011321 is a prime.
Together with 131141112011321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131141112011321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570556005661 + 65570556005662.
It is an arithmetic number, because the mean of its divisors is an integer number (65570556005662).
Almost surely, 2131141112011323 is an apocalyptic number.
131141112011323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141112011323 is an equidigital number, since it uses as much as digits as its factorization.
131141112011323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 131141112011323 its reverse (323110211141131), we get a palindrome (454251323152454).
The spelling of 131141112011323 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twelve million, eleven thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.095 sec. • engine limits •