Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …011010100101000001101110 |
3 | 122012022222010121011022100011 |
4 | 131310112223122211001232 |
5 | 114142103444223220420 |
6 | 1142525221215123434 |
7 | 36423430005324544 |
oct | 3564265332450156 |
9 | 565288117138304 |
10 | 131141112320110 |
11 | 388706a7076882 |
12 | 1286003921357a |
13 | 58237279b8299 |
14 | 245539985bd94 |
15 | 10264344ec95a |
hex | 7745ab6a506e |
131141112320110 has 128 divisors (see below), whose sum is σ = 252376123507200. Its totient is φ = 48987448634880.
The previous prime is 131141112320083. The next prime is 131141112320111. The reversal of 131141112320110 is 11023211141131.
It is a super-2 number, since 2×1311411123201102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131141112320111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2495950440 + ... + 2496002980.
It is an arithmetic number, because the mean of its divisors is an integer number (1971688464900).
Almost surely, 2131141112320110 is an apocalyptic number.
131141112320110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131141112320110 is a deficient number, since it is larger than the sum of its proper divisors (121235011187090).
131141112320110 is a wasteful number, since it uses less digits than its factorization.
131141112320110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55346.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 131141112320110 its reverse (11023211141131), we get a palindrome (142164323461241).
The spelling of 131141112320110 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twelve million, three hundred twenty thousand, one hundred ten".
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