Base | Representation |
---|---|
bin | 11101110100010110101100… |
… | …000001000010000010000101 |
3 | 122012022222011022010102212211 |
4 | 131310112230001002002011 |
5 | 114142104004313303024 |
6 | 1142525222215143421 |
7 | 36423430160110243 |
oct | 3564265401020205 |
9 | 565288138112784 |
10 | 131141122400389 |
11 | 38870701831292 |
12 | 12860040674b71 |
13 | 5823729b0754a |
14 | 245539ad23793 |
15 | 102643533e594 |
hex | 7745ac042085 |
131141122400389 has 2 divisors, whose sum is σ = 131141122400390. Its totient is φ = 131141122400388.
The previous prime is 131141122400377. The next prime is 131141122400443. The reversal of 131141122400389 is 983004221141131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 66386237450625 + 64754884949764 = 8147775^2 + 8047042^2 .
It is a cyclic number.
It is not a de Polignac number, because 131141122400389 - 213 = 131141122392197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141122400339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570561200194 + 65570561200195.
It is an arithmetic number, because the mean of its divisors is an integer number (65570561200195).
Almost surely, 2131141122400389 is an apocalyptic number.
It is an amenable number.
131141122400389 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141122400389 is an equidigital number, since it uses as much as digits as its factorization.
131141122400389 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 40.
The spelling of 131141122400389 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twenty-two million, four hundred thousand, three hundred eighty-nine".
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