131141324013407 has 2 divisors, whose sum is σ = 131141324013408. Its totient is φ = 131141324013406.

The previous prime is 131141324013361. The next prime is 131141324013419. The reversal of 131141324013407 is 704310423141131.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (704310423141131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131141324013407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131141324013607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662006703 + 65570662006704.

It is an arithmetic number, because the mean of its divisors is an integer number (65570662006704).

Almost surely, 2^{131141324013407} is an apocalyptic number.

131141324013407 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141324013407 is an equidigital number, since it uses as much as digits as its factorization.

131141324013407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

Adding to 131141324013407 its reverse (704310423141131), we get a palindrome (835451747154538).

The spelling of 131141324013407 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, thirteen thousand, four hundred seven".