131141324013629 has 2 divisors, whose sum is σ = 131141324013630. Its totient is φ = 131141324013628.

The previous prime is 131141324013607. The next prime is 131141324013631. The reversal of 131141324013629 is 926310423141131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76352119720900 + 54789204292729 = 8737970^2 + 7401973^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141324013629 - 2¹² = 131141324009533 is a prime.

Together with 131141324013631, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131141324013659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662006814 + 65570662006815.

It is an arithmetic number, because the mean of its divisors is an integer number (65570662006815).

Almost surely, 2^{131141324013629} is an apocalyptic number.

It is an amenable number.

131141324013629 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141324013629 is an equidigital number, since it uses as much as digits as its factorization.

131141324013629 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 131141324013629 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, thirteen thousand, six hundred twenty-nine".