Base | Representation |
---|---|
bin | 1011111011010101111100… |
… | …1101000011101001110111 |
3 | 1201102200212102202211122122 |
4 | 2332311133031003221313 |
5 | 3204330220344204142 |
6 | 43520314350150155 |
7 | 2522315266166321 |
oct | 276653715035167 |
9 | 51380772684578 |
10 | 13114132413047 |
11 | 41a67439539a6 |
12 | 15797344b235b |
13 | 741871358933 |
14 | 334a27d8a611 |
15 | 17b1de45d1d2 |
hex | bed5f343a77 |
13114132413047 has 2 divisors, whose sum is σ = 13114132413048. Its totient is φ = 13114132413046.
The previous prime is 13114132413007. The next prime is 13114132413089. The reversal of 13114132413047 is 74031423141131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13114132413047 - 238 = 12839254506103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13114132412998 and 13114132413016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114132413007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066206523 + 6557066206524.
It is an arithmetic number, because the mean of its divisors is an integer number (6557066206524).
Almost surely, 213114132413047 is an apocalyptic number.
13114132413047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114132413047 is an equidigital number, since it uses as much as digits as its factorization.
13114132413047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 13114132413047 its reverse (74031423141131), we get a palindrome (87145555554178).
The spelling of 13114132413047 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thirteen thousand, forty-seven".
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