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13114132430909 is a prime number
BaseRepresentation
bin1011111011010101111100…
…1101001000000000111101
31201102200212102210202011012
42332311133031020000331
53204330220400242114
643520314350405005
72522315266302356
oct276653715100075
951380772722135
1013114132430909
1141a6743966364
121579734500765
13741871363ac3
14334a27d92d2d
1517b1de46363e
hexbed5f34803d

13114132430909 has 2 divisors, whose sum is σ = 13114132430910. Its totient is φ = 13114132430908.

The previous prime is 13114132430851. The next prime is 13114132430911. The reversal of 13114132430909 is 90903423141131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11952162696100 + 1161969734809 = 3457190^2 + 1077947^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114132430909 - 224 = 13114115653693 is a prime.

Together with 13114132430911, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114132430209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066215454 + 6557066215455.

It is an arithmetic number, because the mean of its divisors is an integer number (6557066215455).

Almost surely, 213114132430909 is an apocalyptic number.

It is an amenable number.

13114132430909 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114132430909 is an equidigital number, since it uses as much as digits as its factorization.

13114132430909 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 13114132430909 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thirty thousand, nine hundred nine".