Base | Representation |
---|---|
bin | 1011111011010101111101… |
… | …0100101110001100100101 |
3 | 1201102200212120112220211202 |
4 | 2332311133110232030211 |
5 | 3204330221403003214 |
6 | 43520314501212245 |
7 | 2522315322235244 |
oct | 276653724561445 |
9 | 51380776486752 |
10 | 13114134422309 |
11 | 41a6744aa6548 |
12 | 1579735101085 |
13 | 7418718b034b |
14 | 334a2835095b |
15 | 17b1de7086de |
hex | bed5f52e325 |
13114134422309 has 2 divisors, whose sum is σ = 13114134422310. Its totient is φ = 13114134422308.
The previous prime is 13114134422237. The next prime is 13114134422357. The reversal of 13114134422309 is 90322443141131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11086136272225 + 2027998150084 = 3329585^2 + 1424078^2 .
It is a cyclic number.
It is not a de Polignac number, because 13114134422309 - 236 = 13045414945573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114134422399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557067211154 + 6557067211155.
It is an arithmetic number, because the mean of its divisors is an integer number (6557067211155).
Almost surely, 213114134422309 is an apocalyptic number.
It is an amenable number.
13114134422309 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114134422309 is an equidigital number, since it uses as much as digits as its factorization.
13114134422309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 38.
The spelling of 13114134422309 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, four hundred twenty-two thousand, three hundred nine".
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