Base | Representation |
---|---|
bin | 1011111011010101111101… |
… | …0100101110001111000111 |
3 | 1201102200212120112221001202 |
4 | 2332311133110232033013 |
5 | 3204330221403004341 |
6 | 43520314501213115 |
7 | 2522315322235565 |
oct | 276653724561707 |
9 | 51380776487052 |
10 | 13114134422471 |
11 | 41a6744aa6685 |
12 | 157973510119b |
13 | 7418718b0444 |
14 | 334a28350a35 |
15 | 17b1de70879b |
hex | bed5f52e3c7 |
13114134422471 has 2 divisors, whose sum is σ = 13114134422472. Its totient is φ = 13114134422470.
The previous prime is 13114134422399. The next prime is 13114134422491. The reversal of 13114134422471 is 17422443141131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13114134422471 is a prime.
It is a super-3 number, since 3×131141344224713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114134422491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557067211235 + 6557067211236.
It is an arithmetic number, because the mean of its divisors is an integer number (6557067211236).
Almost surely, 213114134422471 is an apocalyptic number.
13114134422471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114134422471 is an equidigital number, since it uses as much as digits as its factorization.
13114134422471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64512, while the sum is 38.
The spelling of 13114134422471 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, four hundred twenty-two thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •