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13114134424541 is a prime number
BaseRepresentation
bin1011111011010101111101…
…0100101110101111011101
31201102200212120120000220102
42332311133110232233131
53204330221403041131
643520314501230445
72522315322244613
oct276653724565735
951380776500812
1013114134424541
1141a6744aa8197
121579735102425
137418718b1377
14334a283516b3
1517b1de7091cb
hexbed5f52ebdd

13114134424541 has 2 divisors, whose sum is σ = 13114134424542. Its totient is φ = 13114134424540.

The previous prime is 13114134424513. The next prime is 13114134424591. The reversal of 13114134424541 is 14542443141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10760886383641 + 2353248040900 = 3280379^2 + 1534030^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13114134424541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114134424495 and 13114134424504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114134424591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557067212270 + 6557067212271.

It is an arithmetic number, because the mean of its divisors is an integer number (6557067212271).

Almost surely, 213114134424541 is an apocalyptic number.

It is an amenable number.

13114134424541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114134424541 is an equidigital number, since it uses as much as digits as its factorization.

13114134424541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 92160, while the sum is 38.

Adding to 13114134424541 its reverse (14542443141131), we get a palindrome (27656577565672).

The spelling of 13114134424541 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, four hundred twenty-four thousand, five hundred forty-one".