Base | Representation |
---|---|
bin | 10011000101010110110… |
… | …111111100011101001111 |
3 | 11122101000021212011120221 |
4 | 103011112313330131033 |
5 | 132441243132001112 |
6 | 2442243104052211 |
7 | 163514162410252 |
oct | 23052667743517 |
9 | 4571007764527 |
10 | 1311422531407 |
11 | 46619791509a |
12 | 1921b4904067 |
13 | 96888721a71 |
14 | 4768a607099 |
15 | 241a6b28e07 |
hex | 13156dfc74f |
1311422531407 has 2 divisors, whose sum is σ = 1311422531408. Its totient is φ = 1311422531406.
The previous prime is 1311422531387. The next prime is 1311422531479. The reversal of 1311422531407 is 7041352241131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311422531407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311422231407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711265703 + 655711265704.
It is an arithmetic number, because the mean of its divisors is an integer number (655711265704).
Almost surely, 21311422531407 is an apocalyptic number.
1311422531407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311422531407 is an equidigital number, since it uses as much as digits as its factorization.
1311422531407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 1311422531407 its reverse (7041352241131), we get a palindrome (8352774772538).
The spelling of 1311422531407 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred thirty-one thousand, four hundred seven".
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