Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …010100111010100011111 |
3 | 11122101000100011201121112 |
4 | 103011112322213110133 |
5 | 132441243321400023 |
6 | 2442243131052235 |
7 | 163514201353535 |
oct | 23052672472437 |
9 | 4571010151545 |
10 | 1311423231263 |
11 | 466198252992 |
12 | 1921b4ba107b |
13 | 96888908492 |
14 | 4768a74a155 |
15 | 241a6c16478 |
hex | 13156ea751f |
1311423231263 has 2 divisors, whose sum is σ = 1311423231264. Its totient is φ = 1311423231262.
The previous prime is 1311423231253. The next prime is 1311423231271. The reversal of 1311423231263 is 3621323241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311423231263 - 24 = 1311423231247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311423231253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711615631 + 655711615632.
It is an arithmetic number, because the mean of its divisors is an integer number (655711615632).
Almost surely, 21311423231263 is an apocalyptic number.
1311423231263 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311423231263 is an equidigital number, since it uses as much as digits as its factorization.
1311423231263 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15552, while the sum is 32.
Adding to 1311423231263 its reverse (3621323241131), we get a palindrome (4932746472394).
The spelling of 1311423231263 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, two hundred thirty-one thousand, two hundred sixty-three".
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