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1311423252397 is a prime number
BaseRepresentation
bin10011000101010110111…
…010101100011110101101
311122101000100012210121021
4103011112322230132231
5132441243323034042
62442243131334141
7163514201502256
oct23052672543655
94571010183537
101311423252397
11466198267855
121921b4bb1351
1396888914c9b
144768a753b2d
15241a6c1c867
hex13156eac7ad

1311423252397 has 2 divisors, whose sum is σ = 1311423252398. Its totient is φ = 1311423252396.

The previous prime is 1311423252319. The next prime is 1311423252407. The reversal of 1311423252397 is 7932523241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1148442295716 + 162980956681 = 1071654^2 + 403709^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311423252397 - 239 = 761667438509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311423252317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711626198 + 655711626199.

It is an arithmetic number, because the mean of its divisors is an integer number (655711626199).

Almost surely, 21311423252397 is an apocalyptic number.

It is an amenable number.

1311423252397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311423252397 is an equidigital number, since it uses as much as digits as its factorization.

1311423252397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 272160, while the sum is 43.

The spelling of 1311423252397 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, two hundred fifty-two thousand, three hundred ninety-seven".