Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …010101100011101011111 |
3 | 11122101000100012210111101 |
4 | 103011112322230131133 |
5 | 132441243323033234 |
6 | 2442243131333531 |
7 | 163514201502115 |
oct | 23052672543537 |
9 | 4571010183441 |
10 | 1311423252319 |
11 | 466198267794 |
12 | 1921b4bb12a7 |
13 | 96888914c3b |
14 | 4768a753ab5 |
15 | 241a6c1c814 |
hex | 13156eac75f |
1311423252319 has 2 divisors, whose sum is σ = 1311423252320. Its totient is φ = 1311423252318.
The previous prime is 1311423252317. The next prime is 1311423252397. The reversal of 1311423252319 is 9132523241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311423252319 - 21 = 1311423252317 is a prime.
It is a super-3 number, since 3×13114232523193 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 1311423252317, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311423252317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711626159 + 655711626160.
It is an arithmetic number, because the mean of its divisors is an integer number (655711626160).
Almost surely, 21311423252319 is an apocalyptic number.
1311423252319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311423252319 is an equidigital number, since it uses as much as digits as its factorization.
1311423252319 is an evil number, because the sum of its binary digits is even.
The product of its digits is 38880, while the sum is 37.
The spelling of 1311423252319 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, two hundred fifty-two thousand, three hundred nineteen".
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