Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …011010010111101100111 |
3 | 11122101000100111210211021 |
4 | 103011112323102331213 |
5 | 132441243343110043 |
6 | 2442243134552011 |
7 | 163514203026646 |
oct | 23052673227547 |
9 | 4571010453737 |
10 | 1311423410023 |
11 | 466198365221 |
12 | 1921b5068607 |
13 | 9688896b95c |
14 | 4768a79535d |
15 | 241a6c4e3ed |
hex | 13156ed2f67 |
1311423410023 has 2 divisors, whose sum is σ = 1311423410024. Its totient is φ = 1311423410022.
The previous prime is 1311423409939. The next prime is 1311423410029. The reversal of 1311423410023 is 3200143241131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3200143241131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311423410023 - 221 = 1311421312871 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1311423410023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311423410029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711705011 + 655711705012.
It is an arithmetic number, because the mean of its divisors is an integer number (655711705012).
Almost surely, 21311423410023 is an apocalyptic number.
1311423410023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311423410023 is an equidigital number, since it uses as much as digits as its factorization.
1311423410023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1311423410023 its reverse (3200143241131), we get a palindrome (4511566651154).
The spelling of 1311423410023 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, four hundred ten thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •