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1311423410023 is a prime number
BaseRepresentation
bin10011000101010110111…
…011010010111101100111
311122101000100111210211021
4103011112323102331213
5132441243343110043
62442243134552011
7163514203026646
oct23052673227547
94571010453737
101311423410023
11466198365221
121921b5068607
139688896b95c
144768a79535d
15241a6c4e3ed
hex13156ed2f67

1311423410023 has 2 divisors, whose sum is σ = 1311423410024. Its totient is φ = 1311423410022.

The previous prime is 1311423409939. The next prime is 1311423410029. The reversal of 1311423410023 is 3200143241131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3200143241131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311423410023 - 221 = 1311421312871 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311423410023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311423410029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711705011 + 655711705012.

It is an arithmetic number, because the mean of its divisors is an integer number (655711705012).

Almost surely, 21311423410023 is an apocalyptic number.

1311423410023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311423410023 is an equidigital number, since it uses as much as digits as its factorization.

1311423410023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1311423410023 its reverse (3200143241131), we get a palindrome (4511566651154).

The spelling of 1311423410023 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, four hundred ten thousand, twenty-three".